题目是不是这样：(a²-4a+4)分之(2a-6)× (a²-3a)分之(a-2)- (a-2)分之1=2(a-3)/(a-2)²×(a-2)/[a(a-3)]-1/(a-2)=2/[a(a-2)]-1/(a-2)=(2-a)/[a(a-2)]=-1/a=-3
-9分之24
